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MC14XXXBCP bảng dữ liệu(PDF) 10 Page - Motorola, Inc |
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MC14XXXBCP bảng dữ liệu(HTML) 10 Page - Motorola, Inc |
10 / 13 page MOTOROLA CMOS LOGIC DATA MC14560B 10 Inputs Arithmatic Expression for R* (Result) (N = Number of Digits, 10N = Modulus A, B, R are Positive Magnitudes) Outputs AS “1” = Neg BS′ “1” = Neg Cout “1” = Carry (N = Number of Digits, 10N = Modulus A, B, R are Positive Magnitudes) End Around Carry (EAC) “1” = EAC Sign of R “1” = Negative Overflow “1” = Overflow AS “1” = Neg BS′ “1” = Neg Cout “1” = Carry A, B, R are Positive Magnitudes) Carry (EAC) “1” = EAC Sign of R “1” = Negative Overflow “1” = Overflow 0 0 0 R = A + 8 No EAC (“0”) because R is correct result. Since A and B are positive signed, R is positive signed (“0”). When Cout = “0”, there is no carry (R < 10N) and thus no overflow (“0”). 0 0 1 When Cout = “1”, there is a carry (R ≥ 10N) and thus overflow (“1”). 0 1 0 R = A – B = A + (10N – 1 – B) = A – B + 10N – 1 No EAC (“0”) because 9’s complement expression for R is correct result. A v B when Cout = “0”; thus sign of R must be negative (“1”). There is never an overflow when numbers of opposite sign are added. 0 1 1 EAC = “1” because expression for R is in error by 1. A > B when Cout = “1”; thus sign of R must be positive (“0”). There is never an overflow when 1 0 0 R = B – A = B + (10N – 1 – A) = B – A + 10N – 1 No EAC (“0”) because 9’s complement expression for R is correct result. B v A when Cout = “0”; thus sign of R must be negative (“1”). overflow when numbers of opposite sign are added. 1 0 1 EAC = “1” because expression for R is in error by 1. B > A when Cout = “1”; thus sign of R must be positive (“0”). 1 1 0 R = – A – B = (10N – 1 – A) + (10N – 1 – B) = – (A + B) + 2 x 10N – 2 EAC = “1” because 9’s complement expression for R is in error by 1. Since A and B are negative signed. R is negative signed (“1”). When Cout = “0”, there is no Carry (R < 0N) and (A + B) > 10N – 1 indicating overflow (“1”). 1 1 1 10N – 2 When Cout = “1”, there is a carry (R ≥ 10N) and (A + B) v 10N – 1 indicating no overflow (“0”). * Output of Adders Figure 9. Truth Table Generation for EAC, Sign, and Overflow Logic |
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