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công cụ tìm kiếm bảng dữ liệu linh kiện điện tử |
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LM4808M bảng dữ liệu(PDF) 10 Page - National Semiconductor (TI) |
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LM4808M bảng dữ liệu(HTML) 10 Page - National Semiconductor (TI) |
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10 / 13 page  Application Information (Continued) For 70 mW of output power into a 32 Ω load, the required V O- PEAK is 2.12 volts. A minimum supply rail of 2.42V results from adding V OPEAK and VOD. Since 5V is a standard supply voltage in most applications, it is chosen for the supply rail. Extra supply voltage creates headroom that allows the LM4808 to reproduce peaks in excess of 70 mW without clip- ping the signal. At this time, the designer must make sure that the power supply choice along with the output imped- ance does not violate the conditions explained in the Power Dissipation section. Remember that the maximum power dissipation point from Equation 1 must be multiplied by two since there are two independent amplifiers inside the pack- age. Once the power dissipation equations have been addressed, the required gain can be determined from Equation 4. (4) A V =Rf/Ri (5) From Equation 4, the minimum gain is: A V = 1.26 Since the desired input impedance was 20k Ω, and with a gain of 1.26, a value of 27k Ω is designated for R f, assuming 5% tolerance resistors. This combination results in a nominal gain of 1.35. The final design step is to address the band- width requirements which must be stated as a pair of −3 dB frequency points. Five times away from a −3dB point is 0.17dB down from passband response assuming a single pole roll-off. As stated in the External Components section, both R i in conjunction with C i, and Co with RL, create first or- der highpass filters. Thus to obtain the desired frequency low response of 100Hz within ±0.5dB, both poles must be taken into consideration. The combination of two single order filters at the same frequency forms a second order response. This results in a signal which is down 0.34dB at five times away from the single order filter −3dB point. Thus, a frequency of 20Hz is used in the following equations to ensure that the re- sponse is better than 0.5dB down at 100Hz. C i ≥ 1/(2π *20kΩ * 20 Hz) = 0.397µF; use 0.39µF. C o ≥ 1/(2π *32Ω * 20 Hz) = 249µF; use 330µF. The high frequency pole is determined by the product of the desired high frequency pole, f H, and the closed-loop gain, A V . With a closed-loop gain of 1.35 and f H = 100kHz, the re- sulting GBWP = 135kHz which is much smaller than the LM4808 GBWP of 900kHz. This figure displays that if a de- signer has a need to design an amplifier with a higher gain, the LM4808 can still be used without running into bandwidth limitations. www.national.com 10 |
Số phần tương tự - LM4808M |
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Mô tả tương tự - LM4808M |
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